Saturday, October 8, 2011

Why nth order differential eq can be represented by a sisytem of n equations of the first order?

For the same reason as an n bit vector can be represented as a sum of n 1-bit elements. Every order in diff eq is a memory element.

BTW, derivative operator maps  (k+1)-dimensional vector into k-dimensional space. That is why inverse requires one boundary condition to resolve uncertainty.

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